When INT0 is configured as a level interrupt. If the I-bit in SREG and the INT0 bit in EIMSK are set (one), the MCU will jump to the corresponding When an edge or logic change on the INT0 pin triggers an interrupt request, INTF0 becomes set ? Bit 0 – INTF0: External Interrupt Flag 0 When INT1 is configured as a level interrupt. The flag is cleared when the interrupt routine is executed.Īlternatively, the flag can be cleared by writing a logical one to it. If the I-bit in SREG and the INT1 bit in EIMSK are set (one), the MCU will jump to the corresponding When an edge or logic change on the INT1 pin triggers an interrupt request, INTF1 becomes set ? Bit 1 – INTF1: External Interrupt Flag 1 These bits are unused bits in the ATmega48/88/168, and will always read as zero. ![]() ![]() ![]() Program Address Source Interrupt Definitionġ 0x0000 RESET External Pin, Power-on Reset, Brown-out Reset and Watchdog System ResetĢ 0x0002 INT0 External Interrupt Request 0ģ 0x0004 INT1 External Interrupt Request 1ġ2.2.3 EIFR – External Interrupt Flag Register Do I add the atmega i/o header then just do something like "int INTF1 = B00000001"? How do I write a "logical one" to the INTF1 or INTF2 (and is that what I am supposed to do?)? I take it I write "00000001" for INTF1 and "00000010" for INTF2, but not sure how to do that. ![]() I don't know what to do with the information, never used the atmega info directly.
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